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sql/anomalies.sql

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+-- Сигнал: день > 3 средних за предыдущие 7 календарных дней.
+-- Требуется 7 дней истории и ненулевая базовая сумма; пропущенные дни = 0.
+-- Целочисленное сравнение через quotient/remainder исключает overflow
+-- при умножении большой SQLite INTEGER суммы на 3 или 7.
+WITH RECURSIVE calendar(day) AS (
+    SELECT MIN(order_date) FROM facts HAVING COUNT(*) > 0
+    UNION ALL
+    SELECT date(day, '+1 day') FROM calendar
+    WHERE day < (SELECT MAX(order_date) FROM facts)
+), totals AS (
+    SELECT order_date, SUM(revenue_kopecks) AS revenue_kopecks
+    FROM daily_category GROUP BY order_date
+), filled AS (
+    SELECT day AS order_date, COALESCE(revenue_kopecks, 0) AS revenue_kopecks
+    FROM calendar LEFT JOIN totals ON totals.order_date = calendar.day
+), baseline AS (
+    SELECT *, SUM(revenue_kopecks) OVER w AS previous_7_sum_kopecks,
+              COUNT(*) OVER w AS history_days
+    FROM filled WINDOW w AS (ORDER BY order_date ROWS BETWEEN 7 PRECEDING AND 1 PRECEDING)
+), thresholds AS (
+    SELECT *, (previous_7_sum_kopecks / 7) * 3
+               + ((previous_7_sum_kopecks % 7) * 3) / 7 AS threshold_floor_kopecks
+    FROM baseline
+)
+SELECT order_date, revenue_kopecks, previous_7_sum_kopecks,
+       threshold_floor_kopecks
+FROM thresholds
+WHERE history_days = 7 AND previous_7_sum_kopecks > 0
+  AND revenue_kopecks > threshold_floor_kopecks
+ORDER BY order_date;